SSC CHSL 2025 PYQ — Question 68

SSC CHSL - 21 Nov 2025 - Shift 3 • Quantitative Aptitude • Q68

Simplify: (81³⁄⁴ × (1/27)⁻²⁄³) / ((√32 + √8)² − (√32 − √8)²)

Show answer & explanation

Correct answer: A

Explanation

Given:

(81³⁄⁴ × (1/27)⁻²⁄³) / ((√32 + √8)² − (√32 − √8)²)

By the formula:

(a + b)² − (a − b)² = 4ab

81³⁄⁴ = (3⁴)³⁄⁴ = 3³ = 27

(1/27)⁻²⁄³ = 27²⁄³ = (3³)²⁄³ = 3² = 9

Upper part = 27 × 9 = 243

(√32 + √8)² − (√32 − √8)²

= 4 × √32 × √8

= 4 × √256

= 4 × 16

= 64

Value = 243 / 64