SSC CGL 2025 PYQ — Question 74

The correct answer is option 1 i.e. $\frac{3}{4}$.

Given, $\left(\frac{6}{7} \div \frac{12}{21}\right) \div \left(\frac{10}{3} \div \frac{5}{3}\right)$

⇒ $(\frac{6}{7} \times \frac{21}{12}) \div (\frac{10}{3} \times \frac{3}{5})$

⇒ $\frac{3}{2} \div 2$ = $\frac{3}{4}$