SSC CHSL 2024 PYQ — Question 67

SSC CHSL - 09 July 2024 - Shift 4 • Quantitative Aptitude • Q67

Simplify.

[6−2{3−4(4÷14−1)+2÷13}−3×2]\left[ 6 - 2 \left\{ 3 - 4 \left( 4 \div \frac{1}{4} - 1 \right) + 2 \div \frac{1}{3} \right\} - 3 \times 2 \right]

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 102.

[6−2{3−4(4÷14−1)+2÷13}−3×2]\left[ 6 - 2 \left\{ 3 - 4 \left( 4 \div \frac{1}{4} - 1 \right) + 2 \div \frac{1}{3} \right\} - 3 \times 2 \right]

⇒ [6−2{3−4(16−1)+2÷13}−3×2]\left[ 6 - 2 \left\{ 3 - 4 \left(16 - 1 \right) + 2 \div \frac{1}{3} \right\} - 3 \times 2 \right]

⇒ [6−2{3−4×15+2÷13}−3×2]\left[ 6 - 2 \left\{ 3 - 4\times 15 + 2 \div \frac{1}{3} \right\} - 3 \times 2 \right]

⇒ [6 - 2{3 - 60 + 6} - 6]

⇒ [6 - 2{- 51} - 6]

⇒ [6 + 102 - 6]

⇒ 102

Therefore, the value of the given expression is 102.