SSC CHSL 2022 PYQ — Question 63

SSC CHSL - 3 June 2022 - Shift 1 • Quantitative Aptitude • Q63

Simplify: 450+752−125×3100 of 1000−650÷(16−3)450 +752-125\times\frac{3}{100} \ of \ 1000-{650\div(16-3)}

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. -2598

Explanation:

Using the rule of BODMAS in the given question, we get

450+752−125×3100 of 1000−650÷(16−3)450 +752-125\times\frac{3}{100} \ of \ 1000-{650\div(16-3)}

⇒ 450+752−125×30−650÷13450 +752-125\times30-{650\div13}

⇒ 450+752−125×30−50450 +752-125\times30-50

⇒ 450+752−3750−50450 +752-3750-50

⇒ 1202−38001202-3800

⇒ -2598

Hence the required answer is -2,598