SSC CHSL 2024 PYQ — Question 71

SSC CHSL - 08 July 2024 - Shift 3 • Quantitative Aptitude • Q71

Simplify:

414×414−2×414×14+14×144{1\over4}×4{1\over4}-2 ×4{1\over4}×{1\over4}+{1\over4}×{1\over4}

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 16.

According to the given question,

414×414−2×414×14+14×144{1\over4}×4{1\over4}-2 ×4{1\over4}×{1\over4}+{1\over4}×{1\over4}

Applying the rule of BODMAS,

414×414−2×414×14+14×144{1\over4}×4{1\over4}-2 ×4{1\over4}×{1\over4}+{1\over4}×{1\over4}

⇒ 174×174−2×174×14+14×14{17\over4}×{17\over4}-2 ×{17\over4}×{1\over4}+{1\over4}×{1\over4}

⇒ 28916−178+116{289\over16}-{17\over8}+{1\over16}

⇒ 29016−178{290\over16}-{17\over8}

⇒ 25616{256\over16} = 16