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SSC CHSL 2024 PYQ — Question 54

SSC CHSL - 02 July 2024 - Shift 3 • Quantitative Aptitude • Q54

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Simplify:

{(33+23)×227}×{(62+32−42)÷(1412)}\{(3^3 + 2^3) \times \frac{22}{7}\} \times \{(6^2 + 3^2 - 4^2) \div (14 \frac{1}{2})\}

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 220.

{(33+23)×227}×{(62+32−42)÷(1412)}\{(3^3 + 2^3) \times \frac{22}{7}\} \times \{(6^2 + 3^2 - 4^2) \div (14 \frac{1}{2})\}

⇒ {(27 + 8) × 22/7} × {(36 + 9 - 16) ÷ 29/2)}

⇒ {35 × 22/7} × {29 × 2/29}

⇒ 110 × 2 = 220