Simplify: 347−[1612÷{62−(7−212)}]3 \frac{4}{7} - \left[16 \frac{1}{2}\div \left\{6^2 - \left(7 - 2 \frac{1}{2}\right) \right\}\right]374−[1621÷{62−(7−221)}].A6421\frac{64}{21}2164B2521\frac{25}{21}2125C6411\frac{64}{11}1164D2511\frac{25}{11}1125Show answer & explanationCorrect answer: AExplanationThe correct answer is Option 1 i.e. 6421\frac{64}{21}2164. 347−[1612÷{62−(7−212)}]3 \frac{4}{7} - \left[16 \frac{1}{2}\div \left\{6^2 - \left(7 - 2 \frac{1}{2}\right) \right\}\right]374−[1621÷{62−(7−221)}] ⇒ 257−[332÷{36−(7−52)}]\frac{25}{7} - \left[\frac{33}{2}\div \left\{36 - \left(7 - \frac{5}{2}\right) \right\}\right]725−[233÷{36−(7−25)}] ⇒ 257−[332÷{36−(92)}]\frac{25}{7} - \left[\frac{33}{2}\div \left\{36 - \left(\frac{9}{2}\right) \right\}\right]725−[233÷{36−(29)}] ⇒ 257−[332÷(632)]\frac{25}{7} - [\frac{33}{2}\div (\frac{63}{2})]725−[233÷(263)] ⇒ 257−[332×(263)]\frac{25}{7} - [\frac{33}{2}\times (\frac{2}{63})]725−[233×(632)] ⇒ 257−[1121]\frac{25}{7} - [\frac{11}{21}]725−[2111] ⇒ 7521−1121\frac{75}{21} - \frac{11}{21}2175−2111 = 6421\frac{64}{21}2164