SSC CHSL 2024 PYQ — Question 67

SSC CHSL - 04 July 2024 - Shift 3 • Quantitative Aptitude • Q67

Simplify: 347−[1612÷{62−(7−212)}]3 \frac{4}{7} - \left[16 \frac{1}{2}\div \left\{6^2 - \left(7 - 2 \frac{1}{2}\right) \right\}\right].

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 6421\frac{64}{21}.

347−[1612÷{62−(7−212)}]3 \frac{4}{7} - \left[16 \frac{1}{2}\div \left\{6^2 - \left(7 - 2 \frac{1}{2}\right) \right\}\right]

⇒ 257−[332÷{36−(7−52)}]\frac{25}{7} - \left[\frac{33}{2}\div \left\{36 - \left(7 - \frac{5}{2}\right) \right\}\right]

⇒ 257−[332÷{36−(92)}]\frac{25}{7} - \left[\frac{33}{2}\div \left\{36 - \left(\frac{9}{2}\right) \right\}\right]

⇒ 257−[332÷(632)]\frac{25}{7} - [\frac{33}{2}\div (\frac{63}{2})]

⇒ 257−[332×(263)]\frac{25}{7} - [\frac{33}{2}\times (\frac{2}{63})]

⇒ 257−[1121]\frac{25}{7} - [\frac{11}{21}]

⇒ 7521−1121\frac{75}{21} - \frac{11}{21} = 6421\frac{64}{21}