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SSC CGL 2023 PYQ — Question 70

SSC CGL - 25 July 2023 - Shift 2 • Quantitative Aptitude • Q70

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Simplify 256x4−16y4(80x2−20y2)(16x2+4y2)\frac{256x^4 - 16y^4}{(80x^2 - 20y^2)(16x^2 + 4y^2)} .

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 15\frac{1}{5}.

256x4−16y4(80x2−20y2)(16x2+4y2)\frac{256x^4 - 16y^4}{(80x^2 - 20y^2)(16x^2 + 4y^2)}

=(16x2)2−(4y2)25(16x2−4y2)(16x2+4y2)=\frac{(16x^2)^2 - (4y^2)^2}{5(16x^2 - 4y^2)(16x^2 + 4y^2)}

=(16x2−4y2)(16x2+4y2)5(16x2−4y2)(16x2+4y2)=\frac{(16x^2 - 4y^2)(16x^2 + 4y^2)}{5(16x^2 - 4y^2)(16x^2 + 4y^2)}

= 1/5

Therefore, the value of the expression is 1/5.