SarkariPYQ

SSC CGL 2024 PYQ — Question 59

SSC CGL - 10 Sep 2024 - Shift 2 • Quantitative Aptitude • Q59

Back to paper

Simplify: 0.58 × 0.58 × 0.58 − 0.0010.58 × 0.58 + 0.058 + 0.01{0.58\ ×\ 0.58\ ×\ 0.58\ -\ 0.001} \over {0.58\ ×\ 0.58\ +\ 0.058\ +\ 0.01}

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 0.48.

0.58 × 0.58 × 0.58 − 0.0010.58 × 0.58 + 0.058 + 0.01{0.58\ ×\ 0.58\ ×\ 0.58\ -\ 0.001} \over {0.58\ ×\ 0.58\ +\ 0.058\ +\ 0.01}

⇒ (0.58)3−(0.1)3(0.58)2+(0.1)2+0.1×0.058{(0.58)^3 - (0.1)^3}\over{(0.58)^2+(0.1)^2+0.1\times0.058}

We know that,

⇒ (a3 - b3) = (a - b)(a2 + b2 + ab)

⇒ (0.58−0.1)((0.58)2+(0.1)2+0.058)((0.58)2+(0.1)2+0.1×0.058){(0.58-0.1)((0.58)^2+(0.1)^2+0.058)}\over{((0.58)^2+(0.1)^2+0.1\times0.058)}

⇒ 0.58 - 0.1 = 0.48