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SSC CGL 2021 PYQ — Question 52

SSC CGL - 23 Aug 2021 - Shift 1 • Quantitative Aptitude • Q52

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 Simple the following expression:

7×4÷21of4−5÷4×(9−13)+2−2÷87\times 4÷ 21 of 4 - 5 ÷ 4 \times (9 - 13) + 2 - 2 ÷ 8

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Correct answer: A

Explanation

The correct answer is Option 1 i.e 71127 \frac{1}{12}.

7×4÷21of4−5÷4×(9−13)+2−2÷87\times 4÷ 21 of 4 - 5 ÷ 4 \times (9 - 13) + 2 - 2 ÷ 8

Solve the question according to the BODMAS Rule.

⇒ 7×4÷84−5÷4×(−4)+2−2÷87\times 4÷ 84 - 5 ÷ 4 \times (-4) + 2 - 2 ÷ 8

⇒ 7×121−54×(−4)+2−147\times \frac{1}{21} - \frac{5}{4} \times (-4) + 2 - \frac{1}{4}

⇒ 13+7−14 \frac{1}{3} +7- \frac{1}{4}

⇒ 112+7=7112\frac{1}{12}+7=7\frac{1}{12}