Sides of a triangle are 12 cm, 9 cm and 9 cm. What is the radius of the circumcircle of this triangle?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. .
a = 12 cm, b = 9 cm, c = 9 cm
Semi-perimeter formula is (s) = (a + b + c)/2 = (12 + 9 + 9)/2 = 30/2 = 15 cm
Area = √[s(s - a)(s - b)(s - c)]
= √[15(15 - 12)(15 - 9)(15 - 9)]
= √[15 × 3 × 6 × 6]
= 18√5 cm2
Circumradius (R) = abc/[4 × Area of the triangle]
= (12 × 9 × 9)/(4 × 18√5)
= 972/(72√5)
= (27√5)/10
Therefore, the circumradius of the triangle is (27√5)/10 cm.