SSC CHSL 2024 PYQ — Question 58

SSC CHSL - 10 July 2024 - Shift 2 • Quantitative Aptitude • Q58

Shopkeeper A marks up his price for an item at 25% and offers a discount of 15%. The same item is marked at 20% by another shopkeeper B and sold at a discount of 12%. Who gets a better deal in terms of % profit and by what profit percentage does he sell that item?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. A, 6.25%.

Let the cost price (CP) of the item be ₹100

For A:

Marked price (MP) after a 25% markup

MP = 100 + 25% of 100 = 125

Selling price (SP) after a 15% discount

⇒ SP = MP - 15% of 125

⇒ SP = 125 - 15% × 125

⇒ SP = 125 - 18.75 = 106.25

Profit = SP - CP 

⇒ 106.25 - 100 =  6.25

Profit% = 6.25/100 × 100 = 6.25%

Now,

For B:

Marked price (MP) after a 20% markup

⇒ MP = 100 + 20% of 100 = 120

Selling price (SP) after a 12% discount

⇒ SP = MP - 12% of 120

⇒ SP = 120 - 12/100 × 120

⇒ SP = 120 - 14.4 = 105.6

Profit = SP - CP

⇒ 105.6 - 100 = 5.6

Profit% = 5.6/100 × 100 = 5.6%

Thus,

Difference in profit % = 6.25 - 5.6 = 0.65%

Hence, A gets a better deal by 0.65%