SSC CGL 2023 PYQ — Question 59

The correct answer is Option 3 i.e. $29\frac{13}{18}$.

The first distance D₁ = 700 km

The time to cover first distance T₁ = 5 hours

The second distance D₂ = 1012 km

The time to cover second distance T₂ = 11 hours

The average speed = ${Total\ distance}\over {Total\ Time}$

Total distance = D₁ + D₂ = 700 + 1012 = 1712 km

Total time = T₁ + T₂ = 5 + 11 = 16 hours

Now, Average speed = $1712 \over 16$ = 107 km/h

The average speed in m/sec = 107 $\times {5 \over 18}$= $29\frac{13}{18}$ m/sec