Sanju can do a piece of work in 17 days, and Rohan can do the same work in 68 days. Find the time required to complete the same work if they are working on alternate days and Sanju starts the work on the first day
Show answer & explanation
Correct answer: B
Explanation
The Correct answer is option 2 i.e.107/4 days
Given that
Sanju can do a piece of work in 17 days
Rohan can do a piece of work in 68 days
Total work = LCM (17, 68) = 68
The efficiency of Sanju = 68/17 = 4
The efficiency of Rohan = 68/68 = 1
if they are working on alternate days and Sanju starts the work on the first day
In 2 days, work = 1 + 4 = 5
In 26 days, they complete the work = 5× 13 = 65
Remaining 3 work is done by Sanju in 3/4 days
Hence, the time to complete work in = 26 + 3/4 = 107/4 days