SSC CHSL 2024 PYQ — Question 69

SSC CHSL - 09 July 2024 - Shift 1 • Quantitative Aptitude • Q69

Rohan can alone finish a work in 12 days and Hari can alone in 16 days. They both work for 3 days and then Rohan left. After that only Hari works and finishes the work. The total work will be completed in:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 12 days.

Time required for Rohan to finish the work = 12 days

Rohan's one-day work = 1/12

Time required for Hari to finish the work = 16 days

Hari's one-day work = 1/16

Rohan and Hari's one-day work together = (1/12) + (1/16) = 7/48

Work done in 3 days = 3 × (7/48) = 7/16

Remaining work: 1 - (7/16) = 9/16

Time required by Hari to complete the remaining work = (9/16)/(1/16) = 9 days

Total time required = Time worked together + Time Hari worked alone = 3 + 9 = 12 days

Therefore, the total work will be completed in 12 days.