Ravi, Manish and Naveen alone can complete a work in 30 days, 15 days and 10 days respectively. They start the work together but Ravi leaves the work after 2 days of the starting of the work and Manish leaves the work after 3 days more. In how many days Naveen will complete the remaining work?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 1 day
Let total work be LCM of 30,15,10 i.e 30unit
Efficiency = Total work/Time taken
Efficiency of Ravi = 30/30 = 1
Efficiency of Manish = 30/15 = 2
Efficiency of Naveen = 30/10 = 3
They all work together for 2 day ,work done = (3 + 2 + 1) × 2 = 12 unit
work done by Manish and Naveen in next 3 days = (2 + 3) × 3 = 15 unit
Remaining work = 30 - (12 + 15) = 3unit
Remaining work will be done by Naveen in 3/3 = 1 day.