Ravi and Suhas walk from A to B, a distance of 24 km, at a speed of 2 km/h and 4 km/h, respectively. Suhas reaches B, returns immediately and meets Ravi at C. Find the distance from A to C.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e.16 km
Given that
A distance of 24 km from A to B
The speed of Ravi = 2 km/h
The speed of Suhas = 4 km/h
Suhas reaches B, returns immediately and meets Ravi at C
So, the meeting time is constant
thus, The distance ratio of Ravi and Suhas is directly proportional to the speed ratio
Speed ratio of Ravi and Suhas = 2 : 4 = 1 : 2
The distance of Ravi/the distance of Suhas = 1/2
Let the distance of Ravi (A to C) be x km
so, the distance of Suhas is 24 + 24 - x = 48 - x
⇒ x/(48 - x) = 1/2
⇒ 48 - x = 2x
⇒ x = 16 km
Hence, the distance from A to C is 16 km