Rationalize the denominator:47+5\frac{4}{\sqrt{7} + \sqrt{5}}7+54 A(√7 - √5) B2(√7 - √5) C9(7 - √5) D12(√5 - √5) Show answer & explanationCorrect answer: BExplanation47+5\frac{4}{\sqrt{7} + \sqrt{5}}7+54 By the formula: (a+b)(a−b)=a2−b247+5×7−57−5=4(7−5)7−5=4(7−5)2=2(7−5)(a + b)(a - b) = a^2 - b^2 \\ \frac{4}{\sqrt{7} + \sqrt{5}} \times \frac{\sqrt{7} - \sqrt{5}}{\sqrt{7} - \sqrt{5}} = \frac{4(\sqrt{7} - \sqrt{5})}{7 - 5} \\ = \frac{4(\sqrt{7} - \sqrt{5})}{2} \\ = 2(\sqrt{7} - \sqrt{5})(a+b)(a−b)=a2−b27+54×7−57−5=7−54(7−5)=24(7−5)=2(7−5)