SarkariPYQ

SSC CHSL 2023 PYQ — Question 66

SSC CHSL - 09 Aug 2023 - Shift 1 • Quantitative Aptitude • Q66

Back to paper

ΔPQR is right angled at Q. If PQ = 12 cm PR = 13 cm, find tan P + cot R.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 1012\frac{10}{12}.

QR = √(PR2 - PQ2) = √(132 - 122) = √(169 - 144) = √25 = 5

tan P + cot R = (5/12) + (5/12) = 10/12

Therefore, tan P + cot R is 10/12.