Δ PQR is inscribed in a circle. The bisector of ∠P cuts QR at S and the circle at T. If PR = 5 cm, PS = 6 cm and ST = 4 cm, then the length (in cm) of PQ is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 12.
In triangle PQS and PTR,
∠QPS = TPR = θ
∠PQS = ∠PTR (Angle made on the circumference by the same chord)
ΔPQS ≈ ΔPQS
PS/PR = PQ/PT
6/5 = x/(6 + 4)
5x = 60
x = 12