SarkariPYQ

SSC CGL 2022 PYQ — Question 62

SSC CGL - 06 Dec 2022 - Shift 4 • Quantitative Aptitude • Q62

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ΔPQR is an isosceles triangle and PQ = PR = 2a unit, QR = a unit. Draw PX ⊥ QR, and find the length of PX.

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Correct answer: D

Explanation

The correct answer is option 4 i.e.  15a2{ \sqrt{15}a \over 2}.

In triangle PQX,

PQ2 = QX2 + PX2

4a2 = a2/4 + PX2

4a2 - a2/4 = PX2

15a2/4 = PX2

PX = 15a2{ \sqrt{15}a \over 2}