PQ is the diameter of a circle with centre A. M is a point on the circle. If m∠MAP = 110°, then find the value of m∠MQA.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 55°.
∠MAP = 110°
∠QAM = 180° - 110° = 70°
AM = AQ = Radius
So, ΔAQM is a isosceles triangle.
∠AQM = ∠AMQ = x
∠AQM + ∠AMQ + ∠QAM = 180°
⇒ x + x + 70° = 180°
⇒ 2x = 110°
⇒ x = 55°