SarkariPYQ

SSC Selection Post 2024 PYQ — Question 58

SSC Selection Post - Graduation Level - 20 Jun 2024 Shift 3 • Quantitative Aptitude • Q58

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PQ is a diameter of a circle and PS is a chord. If PQ is 82 cm and PS is 80 cm, the distance (in cm) of PS from the center of the circle is:

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Correct answer: B

Explanation

The correct answer is Option 2 i.e. 9.

According to the given question,


Required distance = r2−(c/2)2\sqrt{r^2 - (c/2)^2}

where r = 41 cm and c/2 = 40 cm

Now, distance = 412−402\sqrt{41^2 - 40^2}

⇒ 1681−1600\sqrt{1681 - 1600}

⇒ 81\sqrt{81} = 9 cm