PQ and RS are two parallel chords of a circle of length 10 cm and 24 cm, respectively, and lie on the same side of the centre O. If the distance between the chords is 7 cm, what is the radius (in cm) of the circle?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 13.

OR = OP = x radius of the circle
mn = 7
om = y
So, in triangle OMR
x2 = 144 + y2
x2 - 144 = y2............1
In triangle ONP
x2 = 25 + (y + 7)2
x2 = 25 + y2 + 49 + 14y...........2
Put the value of y2 in equation 1
x2 = 25 + x2 - 144 + 49 + 14y
y = 5
So, the value of x
x2 = 144 + y2 = 144 + 25 = 169
x = 13