SSC GD 2025 PYQ — Question 45

SSC GD Const 2025 (English) - 19 Feb 2025 - Shift 2 • Quantitative Aptitude • Q45

P, Q, R and S can complete a piece of work in 25 days, 30 days, 36 days and 40 days, respectively. They work on a rotation basis with Q working on the first day, S on the second day, P on the third day and R on the fourth day, then again Q on the fifth day and so on. In how much time will the work be completed?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e.  31172531\frac {17} {25} days

Total work = LCM(25,30,36,40) = 1800 units.

Q's efficiency = 1800 ÷ 30 = 60 units per day.

S's efficiency = 1800 ÷ 40 = 45 units per day.

P's efficiency = 1800 ÷ 25 = 72 units per day.

R's efficiency = 1800 ÷ 36 = 50 units per day.

Work in one 4-day cycle = 60 + 45 + 72 + 50 = 227 units.

Number of full 4-day cycles = 1800 ÷ 227 = 7.92 = 7 cycles.

Days for 7 cycles = 7 × 4 = 28 days.

Work done in 7 cycles = 7 × 227 = 1589 units.

Remaining work = 1800 − 1589 = 211 units.

Day 29 (Q) does 60 units; remaining = 211 − 60 = 151 units.

Day 30 (S) does 45 units; remaining = 151 − 45 = 106 units.

Day 31 (P) does 72 units; remaining = 106 − 72 = 34 units.

R's efficiency = 50 units per day, fraction of R-day needed = 34 ÷ 50 = 17/25 day.

Total time = 31 + 17/25 days = 31172531\frac {17} {25} days.