SSC CGL 2025 PYQ — Question 6

SSC CGL Tier II - 20 January 2025 - Shift I • Quantitative Aptitude • Q6

P and Q take part in 400 m race. P runs at 12 km/hr. P gives Q a start of 20 m and still beats him by 13 seconds. The speed of Q is:
(Round up to two decimal places.)

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 10.29 km/hr.

P's speed = 12 km/hr = 12 × (5/18) m/s = 10/3 m/s

Time taken by P to finish the race = Distance/Speed = 400/(10/3) = 120 seconds

Q gets a start of 20 m, so he runs 400 - 20 = 380 m

P beats Q by 13 seconds.

Time taken by Q to finish the race = 120 + 13 = 133 seconds

Q's speed = (380/133) m/s = (380/133) × (18/5) km/h = 10.285... km/h = 10.29 km/h (approx)

Therefore, the speed of Q is 10.39 km/hr.