SSC CGL 2024 PYQ — Question 52

SSC CGL - 11 Sep 2024 - Shift 1 • Quantitative Aptitude • Q52

Directions: Study the given table and answer the question that follows.

The given table shows the number of candidates who appeared (both male and female) in a Public Examination and the percentage of those who qualified in the examination from two states X and Z. Few values are missing in the table (indicated by ------). You will be required to fill them up according to the question.

Year State X State Z
Number of
appeared candidates
Percentage of qualified candidates Number of
appeared candidates
Percentage of qualified candidates
2008 480 70% -------- 70%
2009 560 75% 500 80%
2010 -------- 60% 650 50%
2011 450 89% 720 72%
2012 790 -------- 660 --------

Out of the number of qualified candidates from State X in 2010, the ratio of male to female candidates is 5 : 7. If the number of female qualified candidates from State X in 2010 is 168, what is the number of appeared candidates (both male and female) from State X in 2010?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e. 480.

Qualified candidates from State X = The number of candidates who appeared in State X in 2010 × 60%

Now,

The ratio of male to female candidates is 5 : 7

If the number of female-qualified candidates from State X in 2010 was 168

so,

⇒ 7x = 168

⇒ x = 24

Number of male = 5x = 120

Total qualified candidates from State X in 2010 = 120 + 168 = 288

Percentage of qualified candidates in state X in 2010 = 60%

We know that 60% of the candidates who appeared qualified.

So,

⇒ 60% = 288

⇒ 1% = 480

Thus,

The number of candidates (both male and female) from State X in 2010 was 480