Out of five numbers A, B, C, D and E, the average of the first four numbers A, B, C and D is greater than the average of the last four numbers B, C, D and E by 35. The value of (A – E)/7 is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 20.
(A + B + C + D)/4 − (B + C + D + E)/4 = 35
(A + B + C + D) − (B + C + D + E) = 140
A - E = 140
(A - E)/7 = 140/7 = 20