SSC GD 2023 PYQ — Question 60

The correct answer is option 4 i.e. 8 : 56 a.m.

Total time t₁= 4 hours

Total time t₂ = 3.5 hours

Speed = $Distance \over time$

Relative speed in opposite direction = S₁ + S₂

Let's assume total distance = 56 km

Speed of first train = $56\over 4$ = 14 km/h

Speed of second train = $56\over 3.5$ = 16 km/h

Distance covered by the first train till 8 am, 2 × 14 = 28 km

So, remaining distance, 56 - 28 = 28 km

So, meeting time = $28\over (16 + 14)$ 

⇒ (28/30) × 60 min = 56 min

So, meeting time, 8 am + 56 min = 8 : 56 am