O is the circumcentre of the isosceles Δ ABC. Given that AB = AC = 5 cm and BC = 6 cm. The radius of the circle is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 3.125 cm
| Application |
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AB = AC = 5 cm. (We have assumed to reach answer) AD is perpendicular to BC. BD = DC = 3 cm. In triangle ADB, AD = √AB2 - BD2 ⇒ AD = √52 - 32 ⇒ AD = √25 - 9 = √16 = 4 cm. Let, OA = OC = r cm. ⇒ OD = (4 – r) cm. In triangle OCD: OC2 = OD2 + DC2 ⇒ r2 = (4 - r)2 + 32 ⇒ r2 = 16 + r2 - 8r + 9 ⇒ 8r = 25 ⇒ r = 25/8 = 3.125 cm |
