O is a point in the interior of △ABC such that OA = 12 cm, OC = 9 cm, ∠AOB = ∠BOC = ∠COA and ∠ABC = 60º. What is the length (in cm) of OB?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 6√3

∠AOB = ∠BOC = ∠COA = a (let).
3a = 360
a = 120
∠AOB = ∠BOC = ∠COA = 120°
If one let ∠ABO = then , ∠OBC = (60 - )
Then ∠OCB = and ∠BAO = (60 - ).
So one can say that △AOB is similar to the △BOC,
OB/OA = OC/OB
OB2 = OA × OC
OB = 6√3.