Mohit is five times efficient as Rohit. If Mohit can complete a piece of work in 28 days less than Rohit, then in how many days can Rohit alone complete the same work?
Show answer & explanation
Correct answer: A
Explanation
Correct Answer is option 1 i.e. 35 days
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Understanding |
Application |
Calculation |
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Mohit can complete a piece of work in 28 days less than Rohit. |
Suppose, Rohit complete the work = x days And Mohit complete the work = (x + 28) days |
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Work done by Rohit in 1 day = 1/x Work done by Rohit in 1 day = 1/(x + 28) |
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Mohit is five times efficient as Rohit. |
So, 1/x = 5/(x + 28) ⇒ x = 7 So, Rohit alone can complete the work = 7 × 5 = 35 days |
⇒ 1/x = 5/(x + 28) ⇒ x + 28 = 5x ⇒ 4x = 28 ⇒ x = 7 |