Mohit and Shivam together can complete a piece of work in 4 days, Shivam and Mukesh together can complete it in 5 days and Mohit and Mukesh together can complete it in 6 days. In how many days can Mohit, Shivam and Mukesh together finish the work?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e.
Given that
Mohit and Shivam together complete a work in 4 days
Shivam and Mukesh completed the same work in 5 days
Mohit and Mukesh completed the same work in 6 days
Total work = LCM of (4, 5, 6) = 60
The combined efficiency of Mohit and Shivam = 60/4 = 15
The combined efficiency of Shivam and Mukesh = 60/5 = 12
The combined efficiency of Mohit and Mukesh = 60/6 = 10
Then, The combined efficiency of Mohit, Shivam, and Mukesh = 37/2
Hence, Mohit, Shivam and Mukesh together finish the work = 60/(37/2) = 120/37 =