Manoj travels from City A to City B. If Manoj drives his car at of his normal speed, then he reaches City B 10 minutes late. Find the time (in minutes) that Manoj would have been taken to travel from City A to City B if he drove at his normal speed.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 15.
Let the normal time taken = x minutes
Speed = Distance / Time → So, time is inversely proportional to speed
New speed = 3/5 of normal → Time becomes 5/3 of normal
So, new time = (5/3) × x
Delay = new time - original time = (5/3)x - x = (2/3)x
Given: (2/3)x = 10
⇒ x = (10 × 3)/2 = 15 minutes