Mahesh, Suresh and Raju together can complete a work in 18 days. Mahesh and Suresh together can complete the same work in 72 days. Raju alone can finish the same work in how many days?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 24 days.
Given that
Mahesh, Suresh and Raju together can complete a work in 18 days
Mahesh and Suresh together can complete the same work in 72 days
Total work = LCM (18, 72) = 72
The combined efficiency of Mahesh, Suresh and Raju = 72/18 = 4
The combined efficiency of Mahesh, and Suresh = 72/72 = 1
So, the efficiency of Raju = 4 - 1 = 3
Hence, Raju alone finish the same work in = 72/3 = 24 days