Let x be the least number divisible by 16, 24, 30, 36 and 45, and x is also a perfect square. What is the remainder when x is divided by 123?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 33
| Understanding | Application |
| Tricks |
LCM of the given number LCM of 16, 24, 30, 36 and 45 = 720 |
| Now |
x should be the exact square So 720 × 2 = 1440 not p. square 720 × 3 = 2160 not p. square 720 × 4 = 2880 not p. square 720 × 5 = 3600 perfect square |
| Now |
Reminder 3600/123 So Remainder = 33 |