Let x = (53/4× 153/4+22/35div111/25)/(3/4div11/4+53/5div34/15) . When y is added to x, the result is 7/13 . What is the value of y?

Let x = (53/4× 153/4+22/35div111/25)/(3/4div11/4+53/5div34/…

Let x = $\frac{5\frac{3}{4}\times 15\frac{3}{4}+2\frac{2}{35}\div1\frac{11}{25}}{\frac{3}{4}\div1\frac{1}{4}+5\frac{3}{5}\div3\frac{4}{15}}$ . When y is added to x, the result is $\frac{7}{13}$ . What is the value of y?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. $\frac{4}{13}$

x = $\frac{5 \frac{3}{4}-\frac{3}{7} \times 15 \frac{3}{4}+2 \frac{2}{35} \div 1 \frac{11}{25}}{\frac{3}{4} \div 5 \frac{1}{4}+5 \frac{3}{5} \div 3 \frac{4}{15}}$

= (23/4 - 3/7 × 63/4 + 72/35 ÷ 36/25)/(3/4 ÷ 21/4 + 28/5 ÷ 49/15)

= ( -1 + 10/7)/(13/7)

x = 3/13

y + x = 7/13

y = 7/13 - 3/13 = 4/13.

SSC CGL 2022 PYQ — Question 62