SSC CHSL 2019 PYQ — Question 52

SSC CHSL - 4th July 2019 - Shift 3 • Quantitative Aptitude • Q52

Let ABC ~ QPR and arABC : arPQR = 1 : 16. If AB = 12 cm, BC = 6 cm and AC = 9 cm then PR is equal to:

Show answer & explanation

Correct answer: C

Explanation

Correct Answer is option 3 i.e. 24 cm

Concept

Understanding

Application

Fair calculation

If 2 triangles are similar:

(Area of triangle1/ Area of triangle2) = (Side12/Side22)

Given that:

∆ABC is similar to ∆QPR

And

Area(∆ABC) : Area(∆QPR) = 1 : 16

AB = 12, BC = 6, AC = 9

(Area of ABC/ Area of QPR) = (BC2/PR2)

⇒1/16 = (6/PR)2

⇒ 1/4 = 6/PR

⇒ PR = 24 cm

1/4 = 6/PR

⇒ PR = 4 × 6 = 24