SSC CHSL 2019 PYQ — Question 58

SSC CHSL - 9th July 2019 - Shift 1 • Quantitative Aptitude • Q58

Let ∆ABC ≈ ∆QPR and Ar(ABC)/Ar(QPR) = 4/25, If AB = 12 cm, BC = 8 cm and AC = 10 cm, then QR is equal to:

Show answer & explanation

Correct answer: C

Explanation

Correct Answer is option 3 i.e. 25

Concept

Understanding

Application

If all three angles of 2 triangles are equal, then these two triangles are similar triangles.

And

(Area of triangle1/ Area of triangle2) = (Side12/Side22)

Given

∆ABC ≈ ∆QPR

And

Ar(ABC)/Ar(QPR) = 4/25

Now,

AC2/QR2 = 4/25

⇒ AC/QR = 2/5

⇒ 10/QR = 2/5

⇒ QR = 25