Kamal travels from City A to City B. If Kamal drives his car at of his normal speed, then he reaches City B 54 minutes late. Find the time (in minutes) that Kamal would have taken to travel from City A to City B if he drove at his normal speed.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 18
Let normal time = t minutes
Normal speed = S
Reduced speed = 1/4 × S
So, distance = S × t
When speed = 1/4 × S,
Time taken = distance ÷ (1/4 × S)
= (S × t) ÷ (1/4 × S) = 4t
Given he is 54 minutes late,
4t − t = 54
3t = 54
t = 18