SSC GD 2023 PYQ — Question 44

The correct answer is Option 3 i.e. 3 : 2.

Given:

SP of 1 kg of mixture = Rs. 136.40

Gain = 10%

Formula Used:

$CP = SP \times {100 \over (100 +P)}$

Explanation:

CP of 1 kg mixture = $SP \times {100 \over (100 +P)}$

⇒ $136.40 \times {100 \over 110}$ = Rs. 124

Let the grocer mix x kg of tea worth Rs. 120 per kg with y kg of tea worth Rs. 130 per kg

Cost of (x + y) kg of tea = Rs.(120x + 130y)

Cost of 1 kg of mixture = Rs. 124

Cost of (x + y) kg of mixture = Rs. 124(x + y)

So, 124(x + y) = 120x + 130y

⇒ 124x + 124y = 120x + 130y

⇒ 4x = 6y

⇒ x/y = 3/2

Required Ratio = 3 : 2