In two concentric circles, the radius of circle C2 is less than the radius of circle C1. If AB is a chord of circle C1 of length 16 cm, touching circle C2 at point P, find the length of BP.
Show answer & explanation
Correct answer: C
Explanation
Given:
AB = 16 cm
AB touches C₂ at point P
By the formula:
Radius ⟂ Tangent at point of contact
OP ⟂ AB
Therefore, P is the midpoint of AB.
AB = 16
AP = PB = 16/2
PB = 8
BP = 8 cm