In triangle ABC, X and Y are the points on sides AB and AC, respectively, such that XY is parallel to BC. If XY: BC = 2.5 : 7, what is the ratio of the area of the trapezium BCYX to that of the ∆AXY?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e.
Here, XY : BC = 2.5 : 7
As it is given that XY || BC
So, ∆AXY ~ ∆ABC
(Area of ∆AXY)/ (Area of ∆ ABC) = (XY/BC)2 = (2.5/7)2 = 6.25/49
Now, Area of ∆AXY = 6.25
So area of trapezium BCYX = 49 - 6.25 = 42.75 = 171/25