In triangle ABC, the straight line parallel to the side BC meets AB and AC at the points P and Q, respectively. If AP=QC, the length of AB is 16 cm and the length of AQ is 4 cm, the length (in cm) of CQ is :
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. (2 - 2)
Given:
AQ = CQ
Triangle ABC and triangle APQ are similar
⇒ AP/AB = AQ/AC
⇒ x/16 = 4/(x + 4)
⇒ x(4 + x) = 64
⇒ x2 + 4x - 64 = 0
⇒ x = (2√17 - 2)