SSC CHSL 2019 PYQ — Question 63

SSC CHSL - 8th July 2019 - Shift 1 • Quantitative Aptitude • Q63

In triangle ABC, the length of BC is less than twice the length of AB by 3 cm. The length of the AC exceeds the length of AB by 1 cm. The perimeter of the triangle is 34 cm. The length (in cm) of the smaller side of the triangle is:

Show answer & explanation

Correct answer: A

Explanation

Correct Answer is option 1 i.e. 9

Concept

Understanding

Application

Perimeter of a triangle = Sum of all 3 sides

Given

AC = AB + 1

BC = 2AB – 3

Perimeter of triangle = 34 cm

AB + BC + AC = 34 cm

⇒ AB + 2AB – 3 + AB + 1 = 34

⇒ AB = 36/4 = 9 cm

⇒ AC = 9 + 1 = 10 cm

⇒ BC = 2 × 9 – 3 = 15 cm

Smallest side of triangle = AB = 9 cm