In triangle ABC, ∠C = 90°, and D is the point on CB such that AD is the bisector of ∠A. If AC = 5 cm and BC = 12 cm, then what is the length of AD?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 5√13/3 cm
| Application |
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Given that In ∆ABC, ∠C = 90o and D is a point on CB such that AD is the bisector of ∠A
In right-angled ∆ABC Using Pythagoras Theorem (AB)2 = (AC)2 + (BC)2 (AB)2 = 52 + 122 = 169 AB = √169 = 13 Now using the Angle bisector theorem, we can write (BD/BA) = (CD/CA) (BD/CD) = (BA/CA) = 13/5 Hence BD : DC = 13 : 5 & BC = 12 cm = DC = 5/18 × 12 = 10/3 cm In right-angled triangle ACD Using Pythagoras Theorem (AD)2 = (CD)2 + (AC)2 (AD)2 = (10/3)2 + (5)2 = 325/9 AD = √(5 × 5 × 13)/(3 × 3) = 5√13/3 cm |
