SSC CHSL 2019 PYQ — Question 53

SSC CHSL - 3rd July 2019 - Shift 1 • Quantitative Aptitude • Q53

In triangle ABC, BD ⊥ AC. E is a point on BC such that ∠BEA = x°. If ∠EAC = 38° and ∠EBD = 40°, then the value of x is:

Show answer & explanation

Correct answer: D

Explanation

Correct Answer is option 4 i.e. 88°

Understanding

Application

Given

∠EAC = 38, ∠EBD = 40 and ∠BEA = x

Since BD is perpendicular to AC, ∠BDA = 90

In the figure:

∠BOA is the external angle of triangle BOE

Hence,

∠BOA = ∠OBE + ∠OEB

⇒ ∠BOA = (40 + x)

And

∠AOD = 180 – (40 + x)

⇒ ∠AOD = (140 – x)

Now in triangle AOD:

38 + (140 – x) + 90 = 180

⇒ 268 – x = 180

⇒ x = 268 – 180 = 88°