In the year 1913, which of the following month had 5 Sundays?
I. March
II. December
Show answer & explanation
Correct answer: A
Explanation
I. March 1913:
January (31 days): 3 odd days
February (28 days – 1913 is a common year): 0 odd days
Day of March 1st = Day of January 1st (Wednesday) + 3 (January) + 0 (February) = Wednesday + 3 = Saturday
If March 1st is a Saturday, then March 2nd will be a Sunday.
Sunday dates: 2, 9, 16, 23, and 30.
Conclusion: There were 5 Sundays in March.
II. December 1913:
Odd days from March to November: March (3), April (2), May (3), June (2), July (3), August (3), September (2), October (3), November (2) = Total 23 odd days = 2 odd days (upon dividing 23 by 7).
Day of December 1st = Day of March 1st (Saturday) + 2 = Monday.
If December 1st is a Monday, then the first Sunday will fall on the 7th.
Sunday dates: 7, 14, 21, 28.
Conclusion: There were only 4 Sundays in December.
Option (A) Only I is correct.