In the given figure, P is the centre of the circle. If QS = PR, then what is the ratio of ∠RSP to the ∠TPR?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 1 : 3
Let ∠PQR = ∠PRQ = θ
So, ∠QPR = (π – 2θ)
And, SQ = QP = PR
∴ ∠SPQ = ∠PSQ = θ/2
So, ∠TPR = π – (π – 2θ) – θ/2
= 3θ/2
