SSC CGL 2020 PYQ — Question 53

SSC CGL - 7th March 2020 Shift 1 • Quantitative Aptitude • Q53

In the given figure, MP is tangent to a circle with centre A and NQ is a tangent to a circle with centre B. If MP = 15 cm, NQ = 8 cm. PA = 17 cm and BQ = 10 cm, then AB is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. 14 cm

Understanding/Application

MP is tangent to the circle with center A.

So, MP is perpendicular to AM.

From, triangle PAM -

AM2 + MP2 = PA2

⇒ AM2 + 152 = 172

⇒ AM2 = 64

⇒ AM = 8 cm

Radius of the larger circle = AC = AM = 8 cm

NQ is tangent to the circle with center B. So, NQ is perpendicular to BN.

From, triangle QBN -

BN2 + NQ2 = BQ2

⇒ BN2 + 82 = 102

⇒ BN2 = 36

⇒ BN = 6 cm

Radius of the smalller circle = BC = BN = 6 cm

AB = AC + BC = 8 + 6 = 14 cm